hi :)

On Tue, Oct 14, 2003 at 04:40:04PM -0700, Andrew Morton wrote:
> + *	min_free_kbytes = lowmem_kbytes / sqrt(lowmem_kbytes)

you do have a strange sqrt here ;)

if you do a 'x*=2' at the start of your int_sqrt, your results
are closer to a real sqrt.

then, to get similar min_free_kbytes results, you could do
	min_free_kbytes = int_sqrt(2*lowmem_kbytes);

which is easier to understand, me thinks ;)

-- 
CU,		  / Friedrich-Alexander University Erlangen, Germany
Martin Waitz	//  Department of Computer Science 3       _________
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