Re: VMPLIT question

[Nishanth Aravamudan <nacc@us.ibm.com>]

On 12.08.2006 [07:44:35 -0700], Dave Hansen wrote:
> On Fri, 2006-08-11 at 22:27 -0700, Nishanth Aravamudan wrote:
> > While building a newer kernel for a server (which had been running
> > 2.6.12 or so), I spent some time looking for how to set the VMSPLIT
> > .config options. I searched in menuconfig for VMSPLIT and was given a
> > few responses, all similar to this:
> > 
> >   â?????? Symbol: VMSPLIT_3G [=n]
> >   â?????? Prompt: 3G/1G user/kernel split
> >   â??????   Defined at arch/i386/Kconfig:488
> >   â??????   Depends on: <choice>             
> > 
> > Since depending on "<choice>" is less than helpful, I did an rgrep and
> > found what it actually depends on:
> > 
> >   depends on EXPERIMENTAL && !X86_PAE
> >   prompt "Memory split" if EMBEDDED
> >   default VMSPLIT_3G
> > 
> > and was able to determine that I needed the patch recently submitted by
> > Dave Hansen to enable VMSPLIT for highmem kernels. Is there a reason
> > that menuconfig is not able to tell me this, i.e. this is a known
> > limitation of the choice syntax?
> 
> You need to ask for help with the high-level option, not the actual
> "choice":

The "high-level option" being ...? What did you search for in menuconfig
to get the following? And, in any case, how is it useful to return a
"(null)" symbol name?

>   ??? Symbol: (null) [=y]                                                                         ???
>   ??? Prompt: Memory split                                                                        ???
>   ???   Defined at arch/i386/Kconfig:494                                                          ???
>   ???   Depends on: EXPERIMENTAL && !X86_PAE && EMBEDDED                                          ???
>   ???   Location:                                                                                 ???
>   ???     -> Processor type and features                                                          ???
>   ???   Selected by: EXPERIMENTAL && !X86_PAE && EMBEDDED && m                                    ???

Thanks,
Nish

-- 
Nishanth Aravamudan <nacc@us.ibm.com>
IBM Linux Technology Center