Re: [RFC PATCH] block: warn if blk_stack_limits() undermines atomicity

[Mike Snitzer <snitzer@redhat.com>]

On Tue, Feb 23 2010 at 12:10pm -0500,
Martin K. Petersen <martin.petersen@oracle.com> wrote:

> >>>>> "Mike" == Mike Snitzer <snitzer@redhat.com> writes:
> 
> Mike> For instance, a 512 byte device and a 4K device may be combined
> Mike> into a single logical DM device; the resulting DM device would
> Mike> have a logical_block_size of 4K.  Filesystems layered on such a
> Mike> hybrid device assume that 4K will be written atomically but in
> Mike> reality that 4K will be split into 8 512 byte IOs when issued to
> Mike> the 512 byte device.
> 
> Not really.  It'll be issued as one I/O with a smaller LBA count but an
> identical data payload.

Can you expand on that a bit?  How does a smaller LBA count relate to
this?  On a 512b device the 4K data payload would touch more LBAs.

In any case, a 4K write to a 512b device is not atomic.

> Mike> Using a 4K logical_block_size for the higher-level DM device
> Mike> increases potential for a partial write to the 512b device if
> Mike> there is a system crash.
> 
> That's a definite maybe :)

If you think what I've raised here is overblown then I'd like to
understand why in more detail.

> Mike> [NOTE: setting "misaligned" for this warning is somewhat awkward
> Mike> but blk_stack_limits() return of -1 can be viewed as there was an
> Mike> "alignment inconsistency".  Would it be better to return -1 but
> Mike> avoid setting t->misaligned?]
> 
> I don't have a problem with printing a warning but I don't think this
> qualifies as misalignment on the grounds that the error scenario is in
> the hypothetical bucket and not a deterministic thing.

OK, I was relying on returning -1 so the blk_stack_limits() caller could
provide additional context (via existing warnings) for which device
"increases potential for partial writes" when it gets stacked.

Otherwise all you have is a largely generic warning (as blk_stack_limits
knows nothing about which devices the provided limits belong to).

Mike