Re: [PATCH] net: clear heap allocations for privileged ethtool actions

[Kees Cook <kees.cook@canonical.com>]

Hi Eric,

On Thu, Oct 07, 2010 at 11:31:25PM +0200, Eric Dumazet wrote:
> Le jeudi 07 octobre 2010 à 14:10 -0700, Kees Cook a écrit :
> > Several other ethtool functions leave heap uncleared (potentially) by
> > drivers. Some interfaces appear safe (eeprom, etc), in that the sizes
> > are well controlled. In some situations (e.g. unchecked error conditions),
> > the heap will remain unchanged in areas before copying back to userspace.
> > Note that these are less of an issue since these all require CAP_NET_ADMIN.
> 
> > @@ -775,7 +775,7 @@ static int ethtool_get_regs(struct net_device *dev, char __user *useraddr)
> >  	if (regs.len > reglen)
> >  		regs.len = reglen;
> >  
> > -	regbuf = kmalloc(reglen, GFP_USER);
> > +	regbuf = kzalloc(reglen, GFP_USER);
> >  	if (!regbuf)
> >  		return -ENOMEM;
> >  
> > -- 
> > 1.7.1
> > 
> 
> Are you sure this is not hiding a more problematic problem ?
> 
> Code does :
> 
> reglen = ops->get_regs_len(dev);
> if (regs.len > reglen)
> 	regs.len = reglen;
> regbuf = kmalloc(reglen, GFP_USER);
> 
> So we can not copy back kernel memory.
> 
> However, what happens if user provides regs.len = 1 byte, and driver
> get_regs() doesnt properly checks regs.len and write past end of regbuf
> -> We probably write on other parts of kernel memory

This code is basically a max() call from what I see.

regbuf = kmalloc(max(regs.len, ops->get_regs_len(dev)), GFP_USER);

If the user passes regs.len = 1, it will be ignored in favor of reglen,
so we'll not write past the end of regbuf, unless I'm misunderstanding.

-Kees

-- 
Kees Cook
Ubuntu Security Team