Re: [PATCH v5] Bluetooth: Add hci_h4p driver

[Pavel Machek <pavel@ucw.cz>]

Hi!

> > +static inline void hci_h4p_handle_byte(struct hci_h4p_info *info, u8 byte)
> 
> pretty big function to be inline

Called from just one place, so that should be ok.

> > +static void hci_h4p_rx_tasklet(unsigned long data)
> > +{
> []
> > +	while (hci_h4p_inb(info, UART_LSR) & UART_LSR_DR) {
> []
> > +		pr_debug("0x%.2x  ", byte);
> 
> pr_debug is prefixed by a newline if necessary
> and then <7>, one for each use.
> 
> This will produce a lot of dmesg output lines
> (1 for each byte) and isn't in my opinion
> necessary/useful.

Ok, I just killed it.

> > +	if (set != !!test_bit(H4P_ACTIVE_MODE, &info->pm_flags)) {
> > +		bt_plat_data->set_pm_limits(info->dev, set);
> > +		if (set)
> > +			set_bit(H4P_ACTIVE_MODE, &info->pm_flags);
> > +		else
> > +			clear_bit(H4P_ACTIVE_MODE, &info->pm_flags);
> > +		BT_DBG("Change pm constraints to: %s", sset);
> 
> missing newline

Actually, it is the other way around. BT_DBG adds the newline. I'll
remove it from the rest.

> > +	if (!hdev) {
> > +		printk(KERN_WARNING "hci_h4p: Frame for unknown device\n");
> > +		return -ENODEV;
> > +	}
> 
> Is this possible?

Probably not, removed.

> > +	if (ret != 6)
> > +		return -EINVAL;
> > +
> > +	for (i = 0; i < 6; i++)
> > +		info->bd_addr[i] = bdaddr[i] & 0xff;
> 
> This could also return -EINVAL if bdaddr[i] > 0xff

Why not.

> > +static int hci_h4p_bcm_set_bdaddr(struct hci_h4p_info *info, struct sk_buff *skb)
> > +{
> > +	int i;
> > +	static const u8 nokia_oui[3] = {0x00, 0x1f, 0xdf};
> > +	int not_valid;
> > +
> > +	not_valid = 1;
> > +	for (i = 0; i < 6; i++) {
> > +		if (info->bd_addr[i] != 0x00) {
> > +			not_valid = 0;
> > +			break;
> > +		}
> > +	}
> 
> This seems wrong as addresses can have valid 0 bytes.
> Perhaps use:
> 
> 	if (!is_valid_ether_addr(info->bd_addr))
> 

I am not sure bluetooth rules are same as ethernet. And notice that it
only errors out on 00:00:00:00:00:00 which seems like invalid address
to me.

I fixed the other ones.

Thanks,
									Pavel


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