booting with linux kernel 2.6.32.2

[ranjith kumar <ranjithproxy@gmail.com>]

Hi,

I am using fedora 10.
I downloaded linux kernel 2.6.32.2 and run the follwing commands to
build and install it.

1) make defconfig
2) make
4)make modules
5)make all
6)make modules_install
7)make install

After that the contents of  /boot/grub/menu.lst are:
------------------------------------------------------------------------
  1 # grub.conf generated by anaconda
      2 #
      3 # Note that you do not have to rerun grub after making changes
to this file
      4 # NOTICE:  You have a /boot partition.  This means that
      5 #          all kernel and initrd paths are relative to /boot/, eg.
      6 #          root (hd0,2)
      7 #          kernel /vmlinuz-version ro root=/dev/VolGroup00/LogVol00
      8 #          initrd /initrd-version.img
      9 #boot=/dev/sda
     10 default=2
     11 timeout=5
     12 splashimage=(hd0,2)/grub/splash.xpm.gz
     13 hiddenmenu
     14 title Fedora (2.6.32.2)
     15         root (hd0,2)
     16         kernel /vmlinuz-2.6.32.2 ro
root=UUID=80c4c9bd-8110-4f79-8bdc-dd69e38bf299
     17         initrd /initrd-2.6.32.2.img
     18 title Fedora (2.6.27.5-117.fc10.i686)
     19         root (hd0,2)
     20         kernel /vmlinuz-2.6.27.5-117.fc10.i686 ro
root=UUID=80c4c9bd-8110-4f79-8bdc-dd69e38bf299
     21         initrd /initrd-2.6.27.5-117.fc10.i686.img
     22 title Windows Vista
     23         rootnoverify (hd0,0)
     24         chainloader +1
---------------------------------------------------------------------------------------------------------
1) When I rebooted the machine and selected "Fedora (2.6.32.2)" from
grub's menu,
why fedora(old fedora 10 which was there initially) is booting instead
of linux kernel 2.6.32.2 ???

2) what does "ro root=UUID=80c4c9bd-8110-4f79-8bdc-dd69e38bf299" means
in /boot/grub/menu.lst ?

Thanks in advance.