execve for script don't return ENOEXEC, bug ?

[Valery Reznic <valery_reznic@yahoo.com>]

Hi,

I Have following to scripts:

a.sh
#!/bin/sh
echo "It's a.sh

and b.sh:
#! ./b.sh
echo "It's b.sh"

As per execve man page, script interpreter should not be script itself.
When I run it on my Fedora 8 x86_64 box (with stock kernel, never updated)
under strace I got following:

strace -f -e execve  setarch x86_64  ./b.sh 
execve("/usr/bin/setarch", ["setarch", "x86_64", "./b.sh"], [/* 23 vars */]) = 0
execve("./b.sh", ["./b.sh"], [/* 23 vars */]) = -1 ENOEXEC (Exec format error)
execve("/bin/sh", ["/bin/sh", "./b.sh"], [/* 23 vars */]) = 0
It's b.sh

I.e execve failed as it should

When I run same scripts on Fedora 12 x86_64 box with stock kernel 2.6.31.5-127.fc12.x86_64 I got following:

strace -f -e execve setarch i386  ./b.sh 
execve("/usr/bin/setarch", ["setarch", "i386", "./b.sh"], [/* 41 vars */]) = 0
execve("./b.sh", ["./b.sh"], [/* 41 vars */]) = 0
It's a.sh

I.e execve succeeded, instead of failing with ENOEXEC

Regards,
Valery.

P.S. I am not subscribed to this list, so please CC me