Re: [PATCH] net/ipv4/*, net/core/neighbour.c jiffies cleanup

["Krishna Kumar" <kumarkr@us.ibm.com>]

Hi Linus,

> >
> > In short: It is wrong to do
> >
> >          if (jiffies <= start+HZ)
> >
> > and it is _right_ to do
> >
> >          if (jiffies - start <= HZ)
>
> Actually this last part is wrong, isn't it ? jiffies <= start + HZ is
also
> a correct way to do it, since start+HZ will overflow to the current value
> of jiffies when HZ time elapses. So the above two statements are
IDENTICAL.
>
> No.
>
> Try it out with a few examples. You'll see.
>
>                    Linus

I am sorry, but I still don't see the difference. I wrote a small program
with different
cases, but the values still come same irrespective of the input arguments
to the
checks. Could you tell under what conditions the checks wuold fail ? The
2's
complement  works the same for addition and subtraction. I have included
the
test program below.

Thanks,

- KK

---------------------------------------------------------------------------------------------
/*
     if (jiffies <= start+HZ)
     if (jiffies - start <= HZ)
*/

#define HZ 100

main()
{
     unsigned long start, jiffies;

     /* Case 1 */
     start = ((unsigned long) -1);
     jiffies = start + HZ;
     if (jiffies <= start + HZ) {
           printf("Less Case 1\n");
     }
     if (jiffies - start <= HZ) {
           printf("Less Case 2\n");
     }

     /* Case 2 */
     start = ((unsigned long) -10);
     jiffies = start + HZ + 1;
     if (jiffies <= start + HZ) {
           printf("Less Case 3\n");
     }
     if (jiffies - start <= HZ) {
           printf("Less Case 4\n");
     }

     /* Case 3 */
     start = ((unsigned long) -10);
     jiffies = start + HZ - 1;
     if (jiffies <= start + HZ) {
           printf("Less Case 5\n");
     }
     if (jiffies - start <= HZ) {
           printf("Less Case 6\n");
     }
}