From: Vincent Whitchurch <vincent.whitchurch@axis.com>
To: Sergey Senozhatsky <sergey.senozhatsky@gmail.com>
Cc: Alexey Dobriyan <adobriyan@gmail.com>,
Andrew Morton <akpm@linux-foundation.org>,
Vlastimil Babka <vbabka@suse.cz>,
Kees Cook <keescook@chromium.org>,
Matthew Wilcox <willy@infradead.org>,
<linux-kernel@vger.kernel.org>, <linux-fsdevel@vger.kernel.org>
Subject: Re: [RFC] process /proc/PID/smaps vs /proc/PID/smaps_rollup
Date: Thu, 8 Sep 2022 11:42:18 +0200 [thread overview]
Message-ID: <Yxm4+rGMLtHLUmMU@axis.com> (raw)
In-Reply-To: <20200929024018.GA529@jagdpanzerIV.localdomain>
On Tue, Sep 29, 2020 at 11:40:18AM +0900, Sergey Senozhatsky wrote:
> On (20/09/29 11:05), Sergey Senozhatsky wrote:
> > One of our unprivileged daemon process needs process PSS info. That
> > info is usually available in /proc/PID/smaps on per-vma basis, on
> > in /proc/PID/smaps_rollup as a bunch of accumulated per-vma values.
> > The latter one is much faster and simpler to get, but, unlike smaps,
> > smaps_rollup requires PTRACE_MODE_READ, which we don't want to
> > grant to our unprivileged daemon.
> >
> > So the question is - can we get, somehow, accumulated PSS info from
> > a non-privileged process? (Iterating through all process' smaps
> > vma-s consumes quite a bit of CPU time). This is related to another
> > question - why do smaps and smaps_rollup have different permission
> > requirements?
>
> Hold on, seems that I misread something, /proc/PID/smaps is also
> unavailable. So the question is, then, how do we get PSS info of
> a random user-space process from an unprivileged daemon?
smaps contains a lot of sensitive information, but perhaps smaps_rollup
could be allowed without ptrace rights if the range information is
masked. I've posted a patch here:
https://lore.kernel.org/linux-mm/20220908093919.843346-1-vincent.whitchurch@axis.com/
prev parent reply other threads:[~2022-09-08 9:42 UTC|newest]
Thread overview: 3+ messages / expand[flat|nested] mbox.gz Atom feed top
2020-09-29 2:05 Sergey Senozhatsky
2020-09-29 2:40 ` Sergey Senozhatsky
2022-09-08 9:42 ` Vincent Whitchurch [this message]
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