From: Dmitry Safonov <dima@arista.com>
To: Eric Dumazet <eric.dumazet@gmail.com>, linux-kernel@vger.kernel.org
Cc: 0x7f454c46@gmail.com, "David S. Miller" <davem@davemloft.net>,
Florian Westphal <fw@strlen.de>,
Hannes Frederic Sowa <hannes@stressinduktion.org>,
netdev@vger.kernel.org
Subject: Re: [PATCH] rtnetlink: Synchronze net in rtnl_unregister()
Date: Mon, 25 Feb 2019 23:21:58 +0000 [thread overview]
Message-ID: <d20c023b-33d5-4c48-a404-e2ba05f98a99@arista.com> (raw)
In-Reply-To: <eb7bca34-2b6a-1140-b230-71f333b42807@gmail.com>
Hi Eric,
On 2/25/19 11:09 PM, Eric Dumazet wrote:
> On 02/25/2019 01:27 PM, Dmitry Safonov wrote:
>> While it's possible to document that rtnl_unregister() requires
>> synchronize_net() afterwards - unlike rtnl_unregister_all(), I believe
>> the module exit is very much slow-path.
>
> rtnl_unregister_all() needs the sychronize_rcu() at this moment
> because of the kfree(tab), not because of the kfree_rcu(link, rcu);
I may be wrong here, but shouldn't we wait for grace period to elapse by
the reason that rtnl_msg_handlers are protected by RCU, not only by rtnl?
Like, without synchronize_net() in rtnl_unregister() - what prevents
module exit race to say, rtnetlink_rcv_msg()=>rtnl_get_link()?
>> --- a/net/core/rtnetlink.c
>> +++ b/net/core/rtnetlink.c
>> @@ -308,7 +308,9 @@ int rtnl_unregister(int protocol, int msgtype)
>> rcu_assign_pointer(tab[msgindex], NULL);
>> rtnl_unlock();
>>
>> - kfree_rcu(link, rcu);
>> + synchronize_net();
>> +
>> + kfree(link);
>
>
> I really do not see a difference here (other than this being much slower of course)
>
> If the caller needs rcu_barrier(), then add it in the caller ?
Well, sure - but it seems confusing that rtnl_unregister() will require
synchronize_rcu(), while rtnl_unregister_all() will not.
And I thought no one would care about another synchronize_rcu() in exit
path.
Thanks,
Dmitry
next prev parent reply other threads:[~2019-02-25 23:22 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2019-02-25 21:27 Dmitry Safonov
2019-02-25 23:09 ` Eric Dumazet
2019-02-25 23:21 ` Dmitry Safonov [this message]
2019-02-25 23:27 ` Dmitry Safonov
2019-02-25 23:31 ` Eric Dumazet
2019-02-26 0:09 ` Dmitry Safonov
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=d20c023b-33d5-4c48-a404-e2ba05f98a99@arista.com \
--to=dima@arista.com \
--cc=0x7f454c46@gmail.com \
--cc=davem@davemloft.net \
--cc=eric.dumazet@gmail.com \
--cc=fw@strlen.de \
--cc=hannes@stressinduktion.org \
--cc=linux-kernel@vger.kernel.org \
--cc=netdev@vger.kernel.org \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox
all inboxes | Powered by JetHome®