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From: Yu Kuai <yukuai1@huaweicloud.com>
To: Guillaume Morin <guillaume@morinfr.org>,
	Yu Kuai <yukuai1@huaweicloud.com>
Cc: linux-raid@vger.kernel.org, linux-kernel@vger.kernel.org,
	song@kernel.org, "yukuai (C)" <yukuai3@huawei.com>
Subject: Re: [BUG] possible race between md_free_disk and md_notify_reboot
Date: Sat, 22 Feb 2025 09:08:10 +0800	[thread overview]
Message-ID: <fd4dc27c-501b-404d-6f96-8a4628883ccd@huaweicloud.com> (raw)
In-Reply-To: <Z7iZh56mykLW82SN@bender.morinfr.org>

Hi,

在 2025/02/21 23:19, Guillaume Morin 写道:
> 2) Instead of mddev_free() being called for mddev N+1 like in 1, I wonder
> what's preventing mddev_free() being called for mddev N (the one we're
> iterating about). Something like
> 
> CPU1							CPU2
> list_for_each_entry(mddev, &all_mddevs, all_mddevs) {
> if (!mddev_get(mddev))
>      continue;
> spin_unlock(&all_mddevs_lock);
> 						        mddev_free(mddev) (same mddev as CPU1)
> 
> mddev_free() does not check the active atomic, or acquire the
> reconfig_mutex/md_lock and will kfree() mddev. So the loop execution
> on CPU1 after spin_unlock() could be a UAF.
> 
> So I was wondering if you could clarify what is preventing race 2?
> i.e what is preventing mddev_free(mddev) from being calling kfree(mddev)
> while the md_notify_reboot() loop is handling mddev.

I said already, please take a look how mddev_put() works, mddev_free()
can't be called untill the reference is released after mddev_get().

Thanks,
Kuai


      reply	other threads:[~2025-02-22  1:08 UTC|newest]

Thread overview: 11+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2025-02-19 19:43 Guillaume Morin
2025-02-20  1:26 ` Yu Kuai
2025-02-20  3:05   ` Guillaume Morin
2025-02-20  3:19     ` Yu Kuai
2025-02-20  3:45       ` Guillaume Morin
2025-02-20  4:06         ` Yu Kuai
2025-02-20 11:55           ` Yu Kuai
2025-02-20 13:39             ` Guillaume Morin
2025-02-21  1:27               ` Yu Kuai
2025-02-21 15:19                 ` Guillaume Morin
2025-02-22  1:08                   ` Yu Kuai [this message]

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