* surpring results of test_and_set_bit() and test_and_clear_bit() functions in Linux-2.6.25 kernel at x86_64 architecture
[not found] <2ab84cd80906170340w3ad8b938t64b6d0926b18daa4@mail.gmail.com>
@ 2009-06-17 10:42 ` qingbo yuan
2009-06-29 13:27 ` Petr Tesarik
0 siblings, 1 reply; 2+ messages in thread
From: qingbo yuan @ 2009-06-17 10:42 UTC (permalink / raw)
To: linux-kernel
hi,all
I recently encountered a strange phenomenon about test_and_set_bit()
and test_and_clear_bit().
Here are the comments about these functions in Linux-2.6.25 kernel at
x86_64 architecture:
/**
* test_and_set_bit - Set a bit and return its old value
*/
/**
* test_and_clear_bit - Clear a bit and return its old value
*/
According to the comments, if the old value is '0', then these
functions will return 0 to the caller, and
if the old value is '1', then these functions will return 1. However,
in my experiment, if the old value is '1', I got -1 instead of 1. Here
is the code:
void generos_test_bitmap(void)
{
int cur,ret_clear,ret_set;
unsigned long bitmap =0x3721;
for(cur = find_first_bit(&bitmap,BITS_PER_LONG);cur <
BITS_PER_LONG;cur = find_next_bit(&bitmap, BITS_PER_LONG, cur + 1)){
ret_clear = test_and_set_bit(cur, &bitmap);
ret_set = test_and_clear_bit(cur, &bitmap);
printk("test_and_set bit [%d] ret [%d]\n",cur,ret_set);
printk("test_and_clear bit [%d] ret [%d]\n\n\n",cur,ret_clear);
}
}
And here is the results:
test_and_set bit [0] ret [-1]
test_and_clear bit [0] ret [-1]
test_and_set bit [5] ret [-1]
test_and_clear bit [5] ret [-1]
test_and_set bit [8] ret [-1]
test_and_clear bit [8] ret [-1]
test_and_set bit [9] ret [-1]
test_and_clear bit [9] ret [-1]
test_and_set bit [10] ret [-1]
test_and_clear bit [10] ret [-1]
test_and_set bit [12] ret [-1]
test_and_clear bit [12] ret [-1]
test_and_set bit [13] ret [-1]
test_and_clear bit [13] ret [-1]
Interesting! Let's take a look at the definition of these funtions in
Linux-2.6.25:
static inline int test_and_set_bit(int nr, volatile void *addr)
{
int oldbit;
asm volatile(LOCK_PREFIX "bts %2,%1\n\t"
"sbb %0,%0"
: "=r" (oldbit), ADDR
: "Ir" (nr) : "memory");
return oldbit;
}
static inline int test_and_clear_bit(int nr, volatile void *addr)
{
int oldbit;
asm volatile(LOCK_PREFIX "btr %2,%1\n\t"
"sbb %0,%0"
: "=r" (oldbit), ADDR
: "Ir" (nr) : "memory");
return oldbit;
}
1. bts and btr set/clear the bit and copy the old value to CF flag.
2. sbb %0,%0 equals (%0-(%0+CF)) -> %0
3. %0 -> oldbit
So, if the old bit is '0', these functions return 0;
if the old bit is '1', these functions return -1;
Both of these functions were right if the comments modified as
"test_and_set_bit - Set a bit and return its opposite old value".
Can anybody point out what problems exist in my analysis?
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