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* LKM, problem with simple char from string.
@ 2004-08-16 10:31 authn
  2004-08-16 21:26 ` Randy.Dunlap
  0 siblings, 1 reply; 2+ messages in thread
From: authn @ 2004-08-16 10:31 UTC (permalink / raw)
  To: linux-kernel

Hello,
I am coding a linux kernel module and have problem with some string from user 
space (from execve system call). There is no problem with useing this string 
as a one, for example printk(KERN_ALERT "%s", string) works fine. 
Problem appears when i want to printk or compare single char, in first case it 
is printked with some extra '<1>' and in second case, when i compare it with 
other one, it doesnt fit to real char (it is "connected" with '<1>' in some 
way ?). I tried to copy it to kmalloced buffer:

if ((k_space=(char *)kmalloc(len, GFP_KERNEL))==NULL)
                        return -1;
memcpy_fromfs((void *)k_space, (void *)argv[argc], len); 

but then playing with k_space[i] was the same. 
Short code from module:
                if ((k_space=(char *)kmalloc(len, GFP_KERNEL))==NULL)
                        return -1;
                memset(k_space, '\0', sizeof(k_space));
                memcpy_fromfs((char *)k_space, (char *)argv[argc], len);
                printk(KERN_ALERT"%s\n", k_space);
                printk(KERN_ALERT "%c\n",k_space[i]);
And then i ll have in log file string (from first printk call) and char with 
<1> (from second printk call). It doesnt let me to compare chars.
What it happens ?


Regards, 
apacz

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2004-08-16 10:31 LKM, problem with simple char from string authn
2004-08-16 21:26 ` Randy.Dunlap

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