* [PATCH 6/9] UML - UML/i386 is i386 when running on x86_64
@ 2005-08-29 20:07 Jeff Dike
0 siblings, 0 replies; only message in thread
From: Jeff Dike @ 2005-08-29 20:07 UTC (permalink / raw)
To: akpm
Cc: linux-kernel, user-mode-linux-devel,
Paolo 'Blaisorblade' Giarrusso
>From Paolo Giarrusso - Make a UML/i386 instance running on x86_64 pretend
to be i386 rather than x86_64.
Signed-off-by: Jeff Dike <jdike@addtoit.com>
Index: linux-2.6.12-rc6/arch/um/kernel/user_util.c
===================================================================
--- linux-2.6.12-rc6.orig/arch/um/kernel/user_util.c 2005-08-08 12:32:06.000000000 -0400
+++ linux-2.6.12-rc6/arch/um/kernel/user_util.c 2005-08-12 14:00:34.000000000 -0400
@@ -132,7 +132,12 @@
struct utsname host;
uname(&host);
- strcpy(machine_out, host.machine);
+ /* XXX: crude detection of 32-bit binary. */
+ if (sizeof(long) == 4 && !strcmp(host.machine, "x86_64")) {
+ strcpy(machine_out, "i686");
+ } else {
+ strcpy(machine_out, host.machine);
+ }
}
char host_info[(_UTSNAME_LENGTH + 1) * 4 + _UTSNAME_NODENAME_LENGTH + 1];
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