From: K Prateek Nayak <kprateek.nayak@amd.com>
To: Kayra Cizmeci <kayracizmeci@gmail.com>
Cc: <albin_yang@163.com>, <albinwyang@tencent.com>,
<bsegall@google.com>, <chen.yu@linux.dev>,
<dietmar.eggemann@arm.com>, <juri.lelli@redhat.com>,
<linux-kernel@vger.kernel.org>, <mgorman@suse.de>,
<mingo@redhat.com>, <peterz@infradead.org>, <rostedt@goodmis.org>,
<vincent.guittot@linaro.org>, <vschneid@redhat.com>
Subject: Re: [PATCH] sched/stats: Fix run_delay over-count for proxy-migrated blocked donors
Date: Tue, 27 Oct 2026 11:54:35 +0530 [thread overview]
Message-ID: <4ac4564e-08fb-4639-a89e-a2ad54cee3f7@amd.com> (raw)
In-Reply-To: <auA7AQ_S9iwPHr4d@scheduler.schedules>
Hello Kayra,
On 10/27/2026 11:41 AM, Kayra Cizmeci wrote:
>> So all things considered, I think the following should work unless I'm
>> terribly mistaken yet again :-) I've left my reasoning as comments:
>>
>> diff --git a/kernel/sched/stats.h b/kernel/sched/stats.h
>> index ebe0a7765f98..c4c624deb25b 100644
>> --- a/kernel/sched/stats.h
>> +++ b/kernel/sched/stats.h
>> @@ -239,6 +239,15 @@ static inline void psi_account_irqtime(struct rq *rq, struct task_struct *curr,
>> static inline void sched_info_dequeue(struct rq *rq, struct task_struct *t)
>> {
>> unsigned long long delta = 0;
>> + /*
>> + * If a task is blocked (blocked donor, delayed dequeue task),
>> + * do not account the queued time as runnable. A task that is
>> + * blocking would have already cleared the "last_queued"
>> + * indicator from sched_info_arrive() when it got a chance to
>> + * run on the CPU.
>> + */
>> + if (t->is_blocked)
>> + t->sched_info.last_queued = 0;
>>
>> if (!t->sched_info.last_queued)
>> return;
>> @@ -290,7 +299,23 @@ static void sched_info_arrive(struct rq *rq, struct task_struct *t)
>> */
>> static inline void sched_info_enqueue(struct rq *rq, struct task_struct *t)
>> {
>> - if (!t->sched_info.last_queued)
>> + /*
>> + * "t->is_blocked" is only cleared after the enqueue is done and
>> + * the task is woken up. If the task is blocked, update the
>> + * "last_queued" timestamp to that of last enqueue - if the task
>> + * is still blocked while it leaves the runqueue, this timestamp
>> + * is ignored and is cleared at sched_info_dequeue().
>> + *
>> + * To transition a task back to blocked after wakeup, it has to
>> + * run on the CPU and naturally reach a safe preemption point.
>> + * sched_info_arrive() will do the correct wait time accounting
>> + * based on the last "last_queued".
>> + *
>> + * Any movement of task after being marked not blocked will be
>> + * correctly captured as queued time at enqueue + dequeue
>> + * boundaries when "t->is_blocked" cleared.
>> + */
>> + if (!t->sched_info.last_queued || t->is_blocked)
>> t->sched_info.last_queued = rq_clock(rq);
>> }
>>
>> ---
>>
>> That "t->is_blocked" check in sched_info_enqueue() may not be
>> necessary either but I've left it in there for now since I did my
>> quick testing with it.
>
>
> Hi Prateek,
>
> IMO too doing this with is_blocked would be cleaner.
>
> But I think this not works on a case where a donor is in a different CPU
> from its owner, like:
>
> A holds the mutex M in CPU0, B is the waiter and its on CPU1.
>
> proxy_migrate_task() gets B to CPU0.
>> After that, A suddenly wants to goto CPU1. And it goes.
> Now B goes back to its home CPU next to A.
>
> Now in here, timer starts.
>
> And suddenly A drops the mutex. Now B is not is_blocked.
>
> Because B is back to its home CPU, there is no dequeue.
> Even if there was B is not is_blocked so timer wouldn't be reset.
>
> Normally we need to add the time that task waited for itself.
> But in this case we add the time task waited for its mutex + for itself.
>
> Or am I missssssing something?
Indeed. That is possible and can probably be fixed by doing a
sched_info_enqueue() in proxy_needs_return() for
task_cpu(p) == p->wake_cpu case like:
diff --git a/kernel/sched/core.c b/kernel/sched/core.c
index 04b62c16fa8c..3d261a4e5b0b 100644
--- a/kernel/sched/core.c
+++ b/kernel/sched/core.c
@@ -3838,8 +3838,11 @@ static inline bool proxy_needs_return(struct rq *rq, struct task_struct *p)
* will not apply. But if it did, this check is the safe way around
* and would migrate.
*/
- if (task_cpu(p) == p->wake_cpu)
+ if (task_cpu(p) == p->wake_cpu) {
+ /* Begin wait time accounting before marking !is_blocked. */
+ sched_info_enqueue(rq, p);
return false;
+ }
scoped_guard(raw_spinlock, &p->blocked_lock) {
/* Task is waking up; clear any blocked_on relationship */
---
Not sure if this solution is ugly or not for calling
sched_info_enqueue() out of the enqueue path :-)
--
Thanks and Regards,
Prateek
next prev parent reply other threads:[~2026-10-27 6:24 UTC|newest]
Thread overview: 17+ messages / expand[flat|nested] mbox.gz Atom feed top
2026-10-25 13:07 albin_yang
2026-10-25 19:28 ` Kayra Cizmeci
2026-10-26 13:53 ` albin_yang
2026-10-26 14:48 ` Kayra Cizmeci
2026-10-26 5:46 ` K Prateek Nayak
2026-10-26 13:38 ` albin_yang
2026-10-27 4:11 ` K Prateek Nayak
2026-10-27 6:11 ` Kayra Cizmeci
2026-10-27 6:24 ` K Prateek Nayak [this message]
2026-10-27 6:52 ` Kayra Cizmeci
2026-10-27 9:45 ` K Prateek Nayak
2026-10-27 9:53 ` Kayra Cizmeci
2026-10-27 9:58 ` K Prateek Nayak
2026-10-27 12:09 ` Peter Zijlstra
2026-10-27 12:13 ` Kayra Cizmeci
2026-10-28 3:40 ` K Prateek Nayak
2026-10-28 9:22 ` Peter Zijlstra
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